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a boy 2m tall is standing at some distance from a 30 m tall building. the angle of elevation from his eyes of the top of the building increases from 30° to 60°. find the distance he walked towards the building. |
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Answer» tan 60 =30-2/ab root 3 =28/ab ab = 28/root 3 tan 30 = 28/cb 1/root 3 = 28/ ac + 28/rt 3 ac =28 rt 3 - 28/rt 3 ac =84 - 28/rt 3 ac =56/rt 3 32.34m. Am i right no u r wrong sonu😑 Q show me answer |
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