1.

A boy ''A'' of mass 50kg climbs up a stair case in 10s. Another boy ''B'' of mass 60kg climbs up a same staircase in 15s. The ratio of their power developed by the boys ''A'' and ''B'' is

Answer»

<P>`5/4`
`3/2`
`4/5`
`2/3`

Solution :`"Work done by the boy" .A. (W_(1))=m^(1)gh=50gh`
`"Work done by the boy" .B. (W_(2)=m_(2)gh=60gh`
power develop by`A=p_(1)=w_(1)/t_(1)=(50gh)/10`
power developed by B=is`p_(2)=(60gh)/(15)."then",p_(1)/p_(2)=((50gh)/(10))/((60gh)/(15))=5/4`


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