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A boy and a man carry a uniform pole of length 8 m and of mass 60 kg by supporting it on their shoulders. They are located at the ends of the pole. Where should a load of 90 kg be suspended from boy.s end so that boy carroes only one - third of the total load ? |
Answer» <html><body><p></p>Solution :The mas of pole acts from its centre .<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>.. Let the load placed at a distance .x. from the <a href="https://interviewquestions.tuteehub.com/tag/boy-903339" style="font-weight:bold;" target="_blank" title="Click to know more about BOY">BOY</a>.s end.<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C07_SLV_035_S01.png" width="80%"/><br/>If `N_(1), N_(2)` are the normal <a href="https://interviewquestions.tuteehub.com/tag/reactions-20919" style="font-weight:bold;" target="_blank" title="Click to know more about REACTIONS">REACTIONS</a> on man and boy respectivelt then `N_(1)=(2)/(3)(60+90)g=100 g N`<br/>`N_(2)=(1)/(3)(60+90)g=50g N`<br/><a href="https://interviewquestions.tuteehub.com/tag/taking-1238585" style="font-weight:bold;" target="_blank" title="Click to know more about TAKING">TAKING</a> turning effects about boy.s end .B., we have.<br/>`N_(1)xx8-60g xx 4-90g xx x=0`<br/>or `100 g xx 8-60g xx 4-90g xx x =0`<br/>on solving x = 6.22 m.</body></html> | |