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A boy can throw a stone up to a maximum height of `10 m`. The maximum horizontal distance that the boy can throw the same stone up to will be :A. `20sqrt(2) m`B. `10m`C. `10 sqrt(2) m`D. `20m` |
Answer» Correct Answer - D `H_(max) = (u^(2))/(2 g) rArr 10 = (u^(2))/(2 g) rArr (u^(2))/(g) = 20` `R_(max) = (u^(2))/(2 g) = 20 m` |
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