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A boy is running over a circular track with uniform speed of `10 ms^(-1)`. What is the average velocity for movement of boy from A to (in `ms^(-1)`) ? A. `(10)/(pi)`B. `(40)/(pi)`C. 10D. None of these |
Answer» Correct Answer - D `upsilon_(av)=("Displacement")/("Time")=(2R)/((piR//upsilon))=(2upsilon)/(pi)=(20)/(pi)ms^(-1)` |
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