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A boy is walking away from a well at a speed of `1.0 m//s` in a direction at right angles to the wall. As he walks, he below a whistle steadily. An observer towards whom the boy is walking hears `4.0` beats per second. If the speed of sound is `340 m//s` , what is the frequency of the whistle?A. 480 HzB. 680 HzC. 840 HzD. 1000 Hz |
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Answer» Correct Answer - B The frequency of direct sound of whistle heard by observer is `n_1=(v)/(v-v_S)n=(340)/(340-1)xxn=(340)/(339)n` ..(i) Frequency of sound of whistle reflected by wall is `n_2=(v)/(v+v_S)n=(340)/(341)n` .(ii) Given, `n_1-n_2=4` Therefore, `(340)/(339)n-(340)/(341)n=4` `impliesn=680Hz` |
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