A boy needs to reach the assessment center in 5 hours, the journey its

1.	A boy needs to reach the assessment center in 5 hours, the journey itself is 350 km. If the boy has covered 2/7th of the distance in 2 hours then what is the speed required to reach the destination 30 minutes early than the required time.1. 110 kmph2. 80 kmph3. 100 kmph4. 120 kmph
Answer» Correct Answer - Option 3 : 100 kmph Given: Required distance = 350 km, time 5 hours Covered distance = 2 / 7 of total in 2 hours Condition: given time = 4 hours 30 minutes Formula used: Speed = Distance / time 1 kmph = 5/18 m/s Calculation: Distance left = (1 – (2 / 7) × 350 ⇒ Distance left = (5 / 7) × 350 = 250 Km ⇒ Time left = 4 hours 30 minutes – 2 hour ⇒ 2 hours 30 minutes = 2.5 hr ⇒ Required speed = 250/2.5 = 100 kmph ∴ Boy needs to travel at speed of 100 kmph in order to reach the destination 30 minutes earlier

A boy needs to reach the assessment center in 5 hours, the journey itself is 350 km. If the boy has covered 2/7th of the distance in 2 hours then what is the speed required to reach the destination 30 minutes early than the required time.1. 110 kmph2. 80 kmph3. 100 kmph4. 120 kmph

Answer» Correct Answer - Option 3 : 100 kmph

Given:

Required distance = 350 km, time 5 hours

Covered distance = 2 / 7 of total in 2 hours

Condition: given time = 4 hours 30 minutes

Formula used:

Speed = Distance / time

1 kmph = 5/18 m/s

Calculation:

Distance left = (1 – (2 / 7) × 350

⇒ Distance left = (5 / 7) × 350 = 250 Km

⇒ Time left = 4 hours 30 minutes – 2 hour

⇒ 2 hours 30 minutes = 2.5 hr

⇒ Required speed = 250/2.5 = 100 kmph

∴ Boy needs to travel at speed of 100 kmph in order to reach the destination 30 minutes earlier

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