A boy of height 1m stands in front of a convex mirror. His distance from the mirror is equal to its focal length. The height of his image isA. `0.25 m`B. `0.33 m`C. `0.5 m`D. `0.67 m`

A boy of height 1m stands in front of a convex mirror. His distance fr

1.	A boy of height 1m stands in front of a convex mirror. His distance from the mirror is equal to its focal length. The height of his image isA. `0.25 m`B. `0.33 m`C. `0.5 m`D. `0.67 m`
Answer» Correct Answer - C Let f be foc al length of the convex mirror. According to new cartesiaan sign convention Object distance, ` u = - f`, focal length `= + f` Using mirror formula, `1/u + 1/v = 1/f` `(1)/(-f)+1/v=1/f` or `1/v=1/f+1/f=2/f` or `v = f/2` The image is formed at a distance `f/2` behind the mirro. It is virtual image. Magnification, `m = -(v)/(u) = - ((f//2))/((-f)) = 1/2` Also, `m = ("Height of image"(h_(I)))/(Height of object(h_(O)))` `:. h_(I) = mh_(O) = 1/2 (1m) = 0.5 m`

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A boy of height 1m stands in front of a convex mirror. His distance from the mirror is equal to its focal length. The height of his image isA. `0.25 m`B. `0.33 m`C. `0.5 m`D. `0.67 m`

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