A brass disc is stuck in a hole of a steel plate. Should you heat the system to free the disc from the hole? Given, alpha for brass =19 times 10^(-6@)C^(-1)" and " alpha for steel =12 times 10^(-6@)C^(-1).

A brass disc is stuck in a hole of a steel plate. Should you heat the

1.	A brass disc is stuck in a hole of a steel plate. Should you heat the system to free the disc from the hole? Given, alpha for brass =19 times 10^(-6@)C^(-1)" and " alpha for steel =12 times 10^(-6@)C^(-1).
Answer» <html><body><p></p>Solution :To free the disc from the hole, the system should cooled. <br/> Since `alpha_(brass) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> alpha_(steel)`, and <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a> the radii of the disc and the hole were the same, the disc <a href="https://interviewquestions.tuteehub.com/tag/expands-2076032" style="font-weight:bold;" target="_blank" title="Click to know more about EXPANDS">EXPANDS</a> more on <a href="https://interviewquestions.tuteehub.com/tag/heating-1017297" style="font-weight:bold;" target="_blank" title="Click to know more about HEATING">HEATING</a> and <a href="https://interviewquestions.tuteehub.com/tag/gets-1005751" style="font-weight:bold;" target="_blank" title="Click to know more about GETS">GETS</a> stuck more tightly. On cooling, the disc contracts more than the hole, and thus becomes free.</body></html>