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A brass sphere of mass 5 kg is heated in a furnance to a temperature 500°C and then placed on a large ice block. The mass of ice that will melt in this process will be (specific heat of brass = 500 J kg-1 °C-1 and heat of fusion of ice = 336 kJ kg-1 )(a) 5.25 kg(b) 3.86 kg(c) 2.56 kg(d) 3.72 kg |
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Answer» Answer is : (d) 3.72 kg Fall in temperature of brass sphere, \(\triangle T\) = 500 - 0 = 500°C Heat loss by sphere, Q = \(ms\triangle T\) = 5 x 500 x 500 = 1250 kJ Heat for melting m2 kg of ice, Q2 = m2L = m2 x 336 From principle of calorimetry, = 1250 kJ = m2 x 336 m2 = \(\frac{1250}{336}\) = 3.72 kg |
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