1.

`A+BtoC+D` `DeltaH=-10,000 J mol^(-1)` `DeltaS-33.3 J mol^(-1)K^(-1)` At what temperature the reaction will occur spontaneous from left to right ?A. `=300.3K`B. `gt300.3K`C. `lt300.3K`D. None of these

Answer» Correct Answer - C
`DeltaG=0=0Delta-TDeltaS`
`T=(-10000)/(-3.3)=300.3K` Since `DeltaH&DeltaH` both are negative therefore reaction will be sportaneous at `Tlt300.3K`


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