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A bucket contains 6 blue, 8 red and 9 black pens. If six pens are drawn one by one without replacement, find the probability of getting all black pens?(a) \(\frac{8}{213}\)(b) \(\frac{8}{4807}\)(c) \(\frac{5}{1204}\)(d) \(\frac{7}{4328}\)The question was asked in an online quiz.I would like to ask this question from Discrete Probability topic in section Discrete Probability of Discrete Mathematics |
Answer» RIGHT answer is (b) \(\frac{8}{4807}\) To explain: TOTAL number of PENS = 23, number of pens we have chosen = 6, total number of black pens = 9. According to the combination probability formula it states that ^nCr = \(\frac{N!}{R! (n-r)!}\), where n = total number of outcomes, r = random selection, P = \(\frac{^9C_6}{^{23}C_6} = \frac{8}{4807}\). |
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