1.

A bucket contains 6 blue, 8 red and 9 black pens. If six pens are drawn one by one without replacement, find the probability of getting all black pens?(a) \(\frac{8}{213}\)(b) \(\frac{8}{4807}\)(c) \(\frac{5}{1204}\)(d) \(\frac{7}{4328}\)The question was asked in an online quiz.I would like to ask this question from Discrete Probability topic in section Discrete Probability of Discrete Mathematics

Answer» RIGHT answer is (b) \(\frac{8}{4807}\)

To explain: TOTAL number of PENS = 23, number of pens we have chosen = 6, total number of black pens = 9. According to the combination probability formula it states that ^nCr = \(\frac{N!}{R! (n-r)!}\),

where n = total number of outcomes, r = random selection, P = \(\frac{^9C_6}{^{23}C_6} = \frac{8}{4807}\).


Discussion

No Comment Found

Related InterviewSolutions