1.

A buffer solution containing 0.1 mole of ammonium hydroxide and 0.15 mole of ammonium chloride per litre of the solution. Calculate the pH of the buffer solution. K_b for ammonium hydroxide is 1.8 xx10^(-5).

Answer»

SOLUTION :This is a buffer mixture containing a weak base and its salt. Hence the equation to be USED is
`pOH=pK_b+log.(["salt"])/(["base"])`
`pK_b=log K_b`
`=-log 1.8-log 10^(-5)=4.7447`
`therefore pOH=4.7447+log.(0.15)/(0.10)`
`pOH=4.7447+log 1.5`
`=4.7447+0.1761=4.9208`
`pH+POH=14` `pH+4.9208=14`
`pH=14-4.9208=9.0792`
`PH=9.08`


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