1.

A buffer solution is prepared in which the concentration of NH_(3) is 0.30 M and the concentration of NH_(4)^(+) is 0.20 M. If the equilibrium constant, K_(b) for NH_(3) equals 1.8 xx 10^(-5), what is the pH of this solution (log 2.7 = 043)

Answer»

8.73
9.08
9.43
11.72

Solution :`pOH = pK_(b)LOG.(["SALT"])/(["Base"])`
`= 4.74 + log.(0.20)/(0.30) = 4.74 + (0.301 - 0.477)`
`= 4.74 - 0.176 = 4.56:. PH = 14- 4.56 = 9.44`.


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