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A buffer solution is prepared in which the concentration of `NH_(3)` is 0.30 M and the concentration of `NH_(4)^(+)` is 0.20 M. If the equilibrium constant, `K_(b)` for `NH_(3)` equals `1.8xx10^(-5)`, what is the pH of this solution ?A. 8.73B. 9.08C. 9.43D. 11.72 |
Answer» Correct Answer - C `p_(OH)=pK_(b)+log.(["Salt"])/(["Base"])=4.74+log.(0.20)/(0.30)` `=4.74+(0.301-0.4.74)=4.74-0.176` `=4.56` `:. pH = 14 - 4.56 = 9.44` |
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