A buffer solution of pH 8.3 is prepared from ammonium chloride and ammonium hydroxide. Dissociation constant of ammonium hydroxide is 1.8xx10^(-5). What is the mole proportion of ammonium chloride and ammonium hydroxide?

A buffer solution of pH 8.3 is prepared from ammonium chloride and amm

1.	A buffer solution of pH 8.3 is prepared from ammonium chloride and ammonium hydroxide. Dissociation constant of ammonium hydroxide is 1.8xx10^(-5). What is the mole proportion of ammonium chloride and ammonium hydroxide?
Answer» Solution :pOH = 14 - pH = 14 - 8.3 = 5.7 `pH=pK_(a)+"log"(["SALT"])/(["Base"])rArrpH=-log_(10)K_(a)+"log"(["Salt"])/(["Base"])` `5.7=-log_(10)(1.8xx10^(-5))+"log"([NH_(4)CL])/([NH_(4)OH])rArr5.7=5-log1.8+"log"([NH_(4)Cl])/([NH_(4)OH])` `5.7=5-0.2553+"log"([NH_(4)Cl])/([NH_(4)OH])rArr5.7=4.7447+"log"([NH_(4)Cl])/([NH_(4)OH])` `therefore([NH_(4)Cl])/([NH_(4)OH])=5.7-4.7447=0.9553` `rArr([NH_(4)Cl])/([NH_(4)OH])="anti"log(0.9553)=9.022""` The ratio is 9 : 1.