InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A bulb A containing gas at 1.5 bar pressure was connected to an evacuated vessel of 1.0 `dm^(3)` capacity through a stopcock. The final pressure of the system dropped to 920 mbar at the same temperature. What is the volume of the container A? |
|
Answer» `V_(1)=1.0dm^(3)` `V_(2)=(1.0+V)dm^(3)` `P_(1)=1.5` bar `P_(2)=920` mbar`=0.92` bar Apply `P_(1)V_(1)=P_(2)V_(2)` `(1.5)(1.0)=(1.0+V)(0.92`bar) `1.5=0.92+0.92V` or `0.92=1.5-0.92=0.58` `thereforeV=0.58//0.92=0.6304dm^(3)` |
|