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A bulb B a capacitor C are connected in series to an a.c. source. A dielectric slab is now introduced between the plates of the capacitor. How will the brightness of bulb change ? |
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Answer» Current through the bulb is `I_(v) = (E_(v))/(Z) = (E_(v))/(sqrt(2) + (1)/(omega^(2) C^(2)))` On introducing a dielectric slab between the plates of capacitor, C increases. Z decreases, `I_(v)` increases. Therefore, glow of the bulb increases. |
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