

InterviewSolution
Saved Bookmarks
1. |
A bulb contains `1.6 g` of `O_(2)` contains.A. 0.05 mol of `O_(2)`B. `3.011 xx 10^(22)` molecules of `O_(2)`C. `1.12 L` of `O_(2)` at `STP`D. `1.22 L` of `O_(2)` at `STP` |
Answer» Correct Answer - A::B::C::D a. Moles of `O_(2) = (1.6)/(32) = 0.05` b. Molecules of `O_(2) = 0.05 xx 6.023 xx 10^(23) = 3.011 xx 10^(22)` d. Volume of `O_(2)` at `STP = 0.05 xx 22.4 = 1.12 L` d. `V_(O_(2))` at `SATP = 0.05 xx 24.4 = 1.22 L` |
|