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A bulb of unknown volume V contains an ideal gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5 litre through a stopcock. When the stopcock was opened the pressure at each became 530 mm while the temperature remained constant. Find V in litres. |
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Answer» Solution :Since on openingthe stopcock, the same NUMBER of moles of the gas occupy a VOLUME of (V + 0.5) litre at the same temperature, We apply Boyle.s LAW : `p_(1)V_(1) = p_(2)V_(2)` `1 xx V = (530)/(760) xx (V + 0.5) ""(p_(2) = (530)/(760)"atm")` `V = 1.152` litres. |
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