1.

A bulb of unknown volume V contains an ideal gas at 1 atm pressure. This bulb was connected to another evacuated bulb of volume 0.5 litre through a stopcock. When the stopcock was opened the pressure at each became 530 mm while the temperature remained constant. Find V in litres.

Answer»

Solution :Since on openingthe stopcock, the same NUMBER of moles of the gas occupy a VOLUME of (V + 0.5) litre at the same temperature,
We apply Boyle.s LAW :
`p_(1)V_(1) = p_(2)V_(2)`
`1 xx V = (530)/(760) xx (V + 0.5) ""(p_(2) = (530)/(760)"atm")`
`V = 1.152` litres.


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