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A bullet going with speed 350 m/s enters in a concrete wall and penetrates a distance of 5 cm before coming to rest . Find the deceleration ? |
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Answer» Solution :Given :Speed of the bullet= 350 m/s i.e., u = 350 m/s s = 5 cm v = 0 m/s a = ? Formula :`v^(2) = u^(2) + 2AS` `RARR 0 = u^(2) + 2as` `(or) u^(2) = - 2as` `a = (-u^(2))/(2s)` Deceleration ` a = (-350 XX 350)/(2 xx 0.5)` `= - 12.25 xx 10 ^(5) m//sec^(2)` Negative ANSWER represents retardation.
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