A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity.

A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, p

1.	A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity.
Answer» bullet=10g=0.01kgvelocity of bullet=1.5 sm mass of PLANK=90g=0.09kgTotal momentum before COLLISION=mass of plank × VELOCITY=0.01×1.5+0.09×0=0.015kg sm Total momentum after collision=(mass of bullet +mass of plank )× velocity=0.1kg×V=0.1Vkg sm According to law of CONSERVATION of momentum,Total momentum before collision=Total momentum after collision0.015kg sm =0.1vkg sm velocity ACQUIRED by the plank and the bullet=0.15 sm

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A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity. ​

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A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity.