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A bullet is fired from a gun The force on a bullet is `F =600 -2 xx 10^(5) t` newton. The force reduces to zero just when the bullet leaves barrel Find the impulse imparted to the bullet . |
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Answer» `F =600 -2 xx 10^(5) t` F becomes zero as soon as the bullet leaves the barrel ` 0=600 -2 xx 10^(5) t rArr 600 =2 xx 10^(5) t` `t =3 xx 10^(3) s rArr` Impulse ` =underset(0)overset(t)int Fdt` `=underset(0)overset(t)int(600 -2 xx 10^(5)t) dt =[600t -2 xx 10^(5) (t^(2))/(2)]_(0)^(3xx10^(-3))` `=600 xx 3 xx 10^(-3) -10^(5) xx 9 xx 10^(-6) =0.9 Ns` . |
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