A bullet is fired from agun . If it recoils freely then kinetic energy

1.	A bullet is fired from agun . If it recoils freely then kinetic energyof gun is ………
Answer» equal to the kinetic energy of bullet more then the kinetic energy of bullet less thanthe kineticenergyof bullet equal or less the kineticenergyof bullet . SOLUTION :Suppose mass of gun is M and mass of bullet is m . Both are intially at rest so momentum of system is zero . Now ,when bullet is fired its VELOCITY is v and velocity of gun is V then from the law o conservation f momentum . Intial momentum of system= Final momentum of system ` :. 0 = mv + MV ` ` :. V = - (mv)/M ` ` :. ` Kinetic energy of gun `kE_(r )` `=1/2 MV^(2)` `=1/2 M (-(mv)/M)^(2)` `=m/M (1/2 mv^(2))` `= m/M (kE_(B))` `=m/M ` (kinetic energy of bullet ) but `m lt M , :. kE_(r ) lt kE_(b)`

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