1.

A bullet is fired normally on an immovable wooden plank of thickness 2 m. It loses 20% of its kinetic energy in penetrating a thickness 0.2 m of the plank. The distance penetrated by the bullet inside the wooden plank is

Answer»

0.2m
0.8m
1m
1.5m

Solution :The wood offers a constant retardation. If the BULLET loses 20% of its kinetic energy by PENETRATING 02 m. It can PENETRATE further into `4xx 0.2 = 0.8 m` with the remaining kinetic energy So the total DISTANCE penetrated by the bullet is `0.2 + 0.8 = 1 m`


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