A bullet is fired vertically upwards with a velocity v from the surface planet when it reaches its maximum height, its acceleration due to the planet's gravity is 1/4th of its value at the surface of the planet. If the escape velocity from the planet is vesc=v√N, then the value of N is (ignore energy loss due to atmosphere)

A bullet is fired vertically upwards with a velocity v from the surfac

1.	A bullet is fired vertically upwards with a velocity v from the surface planet when it reaches its maximum height, its acceleration due to the planet's gravity is 1/4th of its value at the surface of the planet. If the escape velocity from the planet is vesc=v√N, then the value of N is (ignore energy loss due to atmosphere)
Answer» A bullet is fired vertically upwards with a velocity $v$ from the surface planet when it reaches its maximum height, its acceleration due to the planet's gravity is $1 / 4$ th of its value at the surface of the planet. If the escape velocity from the planet is $v_{e s c} = v \sqrt{N}$ , then the value of $N$ is (ignore energy loss due to atmosphere)

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