A bullet is fired vertically upwards with velocity v from the surface of a spherical planet. When it reaches its maximum height, its acceleration due to the planet's gravity is 14th of its value at the surface of the planet. If the escape velocity from the planet is v0=v√N, then the value of N is [ignore energy loss due to atmosphere]

A bullet is fired vertically upwards with velocity v from the surface

1.	A bullet is fired vertically upwards with velocity v from the surface of a spherical planet. When it reaches its maximum height, its acceleration due to the planet's gravity is 14th of its value at the surface of the planet. If the escape velocity from the planet is v0=v√N, then the value of N is [ignore energy loss due to atmosphere]
Answer» A bullet is fired vertically upwards with velocity $v$ from the surface of a spherical planet. When it reaches its maximum height, its acceleration due to the planet's gravity is $\frac{1}{4}$ th of its value at the surface of the planet. If the escape velocity from the planet is $v_{0} = v \sqrt{N}$ , then the value of $N$ is [ignore energy loss due to atmosphere]

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