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A bullet mass 10gm is fired from a gun of mass 1 kg . If the recoil velocity is 5 `m//s`, the velocity of the muzzle is |
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Answer» Conservation of linear momentum gives `m_(1)v_(1) + m_(2)v_(2) = 0 rArr m_(1)v_(1) = -m_(2)v_(2)` `rArr v-(1) = -(m_(2)v_(2))/(m_(1) = 500 m//s` Given, `m_(1) = 10 g = (10/1000) kg` `m_(2) = 1kg` and `v_(2) = -5 m//s` `therefore` Velocity of muzzle, `v-(1) = (+1 xx 5)/(10//1000)= 500 m//s` |
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