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A bullet moving with speed 150m//s strikes a tree and penetrates 3.5cm before stopping . Find the magnitude of its acceleration and the time taken to stop . |
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Answer» Solution :`u=150m//s,s=3.5cm=0.035m, V=0, v^(2)-u^(2)=2AS` `0-150^(2)=2 xx a xx 0.035` a=`(-150xx150)/(2xx0.035)=-3.214xx10^(5) m^(-2)` TIME`=(v-u)/a=(0-150)/(3.24xx10^(5))=(-150)/(3.24xx10^(5))=4.67xx10^(-4) sec` |
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