A bullet of m ass 10 g m oving horizontal w ith a velocity of 400 ms^(-1) strikes a w ood block of m a ss 2 kg w h ic h is s u s p e n d e d by lig h t inex ten sib le strin g of length 5 m. As resu lt the c e n tre of gravity of th e block fo und to rise a v ertical distan ce of 10 cm . The sp eed of the bullet after it em erges on horizontally from the block will b e ......

A bullet of m ass 10 g m oving horizontal w ith a velocity of 400 ms^(

1.	A bullet of m ass 10 g m oving horizontal w ith a velocity of 400 ms^(-1) strikes a w ood block of m a ss 2 kg w h ic h is s u s p e n d e d by lig h t inex ten sib le strin g of length 5 m. As resu lt the c e n tre of gravity of th e block fo und to rise a v ertical distan ce of 10 cm . The sp eed of the bullet after it em erges on horizontally from the block will b e ......
Answer» 120 `ms^(-1)` 160 `ms^(-1)` 100 `ms^(-1)` 80 `ms^(-1)` Solution : Momentumconvertationalrule `(10)/( 1000)xx 400+ 2xx 0 = 2 xx v_(1)+ (10)/( 1000) xx v_(2)` Usingworkenergyrule MGH `=(1)/(2) Mv_(1) 2` `2 xx10 xx 0.1= (1)/(2)xx 2 xxv_(1)^(2)` Usingequation(1) `v_(1)= 1.40m//s` `4 =2xx 1.40+ 0.01v_(2)` `4-2.80= 0 .01v_(2)` `(1.20)/(0.01) =v_(2)` `v_(2) = 120 ms^(-1)`