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A bullet of mas m moving at a speed v hits as ball of mass M kept at rest. A small prt hving mass m breaks from the ball and sticks to the bullet. The remaining ball is found to move at a speed `v_1` in the direction of the bullet. Find the velocity of the ulet after the collision. |
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Answer» Mass of the bullet =m and speed =v Mass of the ball =M `m^1`= fractioN/Al mass from the ball Using law of conservation of momentum `mv+0=(m^1+m)v^1+(M-m^)v_1` Where `v^1=fiN/Al velocity of the bullet + fractioN/Al mass` `rarr v^1=(mv-(M-m)v_1)/(m+m^1)` |
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