A bullet of mass 2.5 g moving with a velocity of 500 ms^(-1) enters a wooden block and comes out of it with a velocity of 100 ms^(-1). Find the work done by the bullet while passing through the wooden block.

A bullet of mass 2.5 g moving with a velocity of 500 ms^(-1) enters a

1.	A bullet of mass 2.5 g moving with a velocity of 500 ms^(-1) enters a wooden block and comes out of it with a velocity of 100 ms^(-1). Find the work done by the bullet while passing through the wooden block.
Answer» Solution :Mass `m = 2.5 g = 2.5 xx 10^(-3)` kg, Initial VELOCITY U = 500 m/s , Final velocity v = 100 m/s By WORK energy theorem, `W = (1)/(2) m u^(2) - (1)/(2) mv^(2) = (1)/(2) xx 2.5 xx 10^(-2) [(500)^(2) - (100)^(2)]` `= 1.25 xx 10^(-3) xx 10^(4) [25 - 1] therefore` Work done = 300 J