a bullet of mass 20 gram is fired with velocity of 1200m/sec after pas

1.	a bullet of mass 20 gram is fired with velocity of 1200m/sec after passing through a mud wall of 2m thick its velocity decreases to 200 m/sec what is average resistance offered by the mud wall?
Answer» Answer: EXPLANATION: use FORMULA v^2=u^2+2as v=200m/sec u=1200m/sec s=2m 200^2=1200^2+2a2 -1410^5 = 4a a = -3.510^5 i.e retardation F=ma =2010^-3 3.5*10^5 =7000N (average RESISTIVE force OFFERED)

a bullet of mass 20 gram is fired with velocity of 1200m/sec after passing through a mud wall of 2m thick its velocity decreases to 200 m/sec what is average resistance offered by the mud wall?

Answer»

Answer:

EXPLANATION:

use FORMULA v^2=u^2+2as

v=200m/sec

u=1200m/sec

s=2m

200^2=1200^2+2*a*2

-14*10^5 = 4*a

a = -3.5*10^5

i.e retardation

F=m*a

=20*10^-3 * 3.5*10^5

=7000N (average RESISTIVE force OFFERED)