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InterviewSolution
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A bullet of mass `20g` is fired horizontly with a velocity of `150ms^(-1)` from a pistol of maass `2kg`. What is the recoil velocity of the pistol? |
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Answer» Here, `m_(1)= 20g =20/(1000)kg= 1/50kg, v_(1)= 150ms^(-1), m_(2)= 2 kg, v_(2)=?` As `m_(1)v_(1)+m_(2)v_(2)=0 v_(2) = -(m_(1)v_(1))/(m_(2))= -1/50xx(150)/2= -1.5m//s` |
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