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A bullet of mass 25 g moving withvelocity of 500 ms^(-1) enters into a wooden block and comes out of it with a velocity of 100 ms^(-1). Find the work done by the bullet while passing through the wooden block. |
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Answer» Solution :`m=25xx10^(-3)KG, U=500 m//s, v=100 m//s` Work energy THEOREM `W=(1)/(2) mv^(2)-(1)/(2)m u^(2)` `=(1)/(2)xx25xx10^(-3)[(100)^(2)-(500)^(2)]=3000J` |
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