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A bullet of mass 25g moving with a velocity of 500 ms^(-1) enters into a wooden block and comes out of it with a velocity of 100 ms^(-10. Find the work done by the bullet while passing through the wooden block.

Answer» <html><body><p></p>Solution :`m= 25 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3) kg, u= 500m//s, v= 100m//s` <br/> Work energy theorem `W= (1)/(2) mv^(2)- (1)/(2) m u^(2)` <br/> `=(1)/(2) xx 25 xx 10^(-3) [(100)^(2)- (<a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a>)^(2)]= <a href="https://interviewquestions.tuteehub.com/tag/300j-306456" style="font-weight:bold;" target="_blank" title="Click to know more about 300J">300J</a>`</body></html>


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