A bullet of mass `50 g` is fired from below into the bob of mass `450 g` of a long simple pendulum as shown in figure. The bullet remains inside the bob and the bob rises through a height of `1.8 m`. find the speed of the bullet.

A bullet of mass `50 g` is fired from below into the bob of mass `450

1.	A bullet of mass `50 g` is fired from below into the bob of mass `450 g` of a long simple pendulum as shown in figure. The bullet remains inside the bob and the bob rises through a height of `1.8 m`. find the speed of the bullet.
Answer» Let the speed of the bullet be `v`. Let the common velocity of the bullet and the bob, after the bullet is embedded into the bob, be `v`. By the principle of conservation of linear momentum. `V=((0.05kg)v)/(0.45g+0.05kg)=v/10` The string becomes loose and the bob will go up with a deceleration of `g=m//s^(2)`. As it comes rest at a height of `1.8 m`, using the equation `v^(2)=u^(2)+2ax`, we get `1.8m=((v/10)^(2))/(2xx10m//s^(2))` or `v=60m//s`

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A bullet of mass `50 g` is fired from below into the bob of mass `450 g` of a long simple pendulum as shown in figure. The bullet remains inside the bob and the bob rises through a height of `1.8 m`. find the speed of the bullet.

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