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A bullet of mass 50 g is moving with a velocity of 500 m s-1. It penetrated 10 cm into a still target and comes to rest. Calculate: (a) the kinetic energy possessed by the bullet, (b) the average retarding force offered by the target. |
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Answer» Mass of bullet = 50g = 0.05kg Velocity = 500m/s Distance penetrated by the bullet = 10cm = 0.1m (a) Kinetic energy of the bullet = 1/2 x mass x (velocity)2 = 1/2 ×0.05 ×(500)2 = 12 ×0.05 ×500 ×500=6250 J (b) Work done by the bullet against the material of the target= resistive force x distance 6250 = resistive force × 0.1m Resistive force = 62500 N |
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