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A bullet of mass m moving with velocity u passes through a wooden block of mass M=nm as shown in figure. The block is resting on a smooth horizontal floor. After passing through the block, velocity of the bullet becomes v. Its velocity relative to the block is |
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Answer» Solution :`m u =MV + mn v ^(-1) (or) v ^(1) = ((u -v)/( N)) THEREFORE` velocity of bullet relative to block will be `v _(R) = v - v ^(i) = v - ((u-v)/( n)) = ((1+n)v -u)/( n )` |
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