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A bullet of mass m moving with velocity u passes through a wooden block of mass M = nm as shown in figure. The block is resting on a smooth horizontal floor. After passing through the block, velocity of the bullet becomes v. Its velocityrelative to the block is |
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Answer» SOLUTION :Let V. be the velocity of block. Then fromconservation of LINEAR MOMENTUM. `m u = mv+mnv^(1)(or)v^(1)=((u-v)/(n))` `therefore` velocity of bullet relative to block will be `v_(r) =v-v^(-1)=v-((u-v)/(n))=((1+n)v-u)/(n)` |
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