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A bus decreases its speed from 80 km h-1 to 60 km h-1 in 5s. Find the acceleration of the bus. |
Answer» Initial velocity of the bus u = 80 kmh-1 80 x \(\frac{5}{18}\) = 22.22 m/s 60 x \(\frac{5}{18}\) = 16.66 m/s Final velocity, V = 60 km/h time taken to decrease the velocity of bus, t = 5 seconds acceleration, a = 5 seconds Velocity a = \(\frac{v-u}{t}\) = \(\frac{16.66-22.22}{5}\) = -1.112 ms-2. |
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