Saved Bookmarks
| 1. |
A bus starting from rest masses with a uniform acceleration of 2 m/s for 4 minutes. a)find the speed acquired. b)find the distance travelled |
|
Answer» Given : INITIAL velocity, U = 0 m/s (as it is starting from rest) Acceleration, a = 2 m/s² Time, t = 4 minutes To find : Speed acquired, v Distance travelled, s According to the question, Note : 1 MINUTE = 60 seconds 4 minutes = 4 × 60 = 240 seconds By using Newtons FIRST equation of motion, ➞ v = u + at Where, v = Final velocity u = Initial velocity a = Acceleration t = Time ➞ Substituting the values, ➞ v = 0 + 2 × 240 ➞ v = 0 + 480 ➞ v = 480 So,the speed acquired is 480 m/s. Now, By using Newtons third equation of motion, ➞ s = ut + ½ at² Where, s = Distance u = Initial velocity a = Acceleration t = Time ➞ Substituting the values, ➞ s = 0 × 240 + ½ × 2 × 240 × 240 ➞ s = 0 + 57600 ➞ s = 57600 So,the distance travelled is 57600 meters. |
|