A bus starts from rest accelerating uniformly with 4ms^(-1)at t =10s a stone is dropped out of a window of the bus 2mhigh what are the (i) magnitude of velocity and (ii) accelearatio of the stone at 10.2 s take g=10 ms^(-2)

A bus starts from rest accelerating uniformly with 4ms^(-1)at t =10s a

1.	A bus starts from rest accelerating uniformly with 4ms^(-1)at t =10s a stone is dropped out of a window of the bus 2mhigh what are the (i) magnitude of velocity and (ii) accelearatio of the stone at 10.2 s take g=10 ms^(-2)
Answer» Solution :Given Acceleration`=4ms^(-2)` Time=- 10s (i)horizontalvelocityof the busor the stoneat t= 10 is `v_(x) = U +at = 0 + 4 xx 10` forverticalmotionof THESTONE `u= 0a=g= 10 ms^(-2)t =10.2-10=0.2s` `v_(y)=0+10 xx 0.22ms^(-2)` Magnitudeof teh resultantvelocityof the stone is `v= sqrt( v^(2) + v^(2)) = sqrt(40^(2) +2^(2))` (ii) Afterteh stoneis droppeditsaccelerationalonghorizontal is ZERO. it has only averticalacceleration of `10 ms^(-2)`