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(a c),B+ C2in a triangle ABC, write cosin terms of angle A. |
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Answer» A+B+C = 180 (ASP of trianlge) ~ B + C = 180 - A ~ cos (B + C) / 2 = cos (180 - A) / 2 ~ cos (180/2 - A/2)~ cos (90 - A/2) ~ sin (A/2) Therefore, cos (B + C/2) = sin (A/2) |
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