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A cable consisting of a wire `3 mm` thick dielectric of relative permitively 10. Calculate the capacitance of `1 km` length of the cable. |
Answer» Correct Answer - `0.506 muF` Here `C_(1) = 3 muF, C_(2) = 6 muF` `r_(b) = 1.5 + 3 = 4.5 mmn = 4.5xx10^(3) m` `L = 1 km = 10^(3) m , K = 10 , C = ?` `C = (2pi in_(0) L K)/(2.303 log_(10) ((r_(b))/(r_(a)))) = (2pi xx 8.85xx10^(-12)xx10^(3)xx10)/(2.303 log ((4.5xx10^(-3))/(1.5xx10^(-3))))` `= 50.6xx10^(-8) F = 0.506 mu F` |
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