(a) Calculate the degree of dissociation 'A' and 'B' are dilute . The limiting molar conductivity of 'B' increases to a smaller extent while that 'A' increase to a much larger extent comparatively . Which of the two is a strong electrolyte ? Justify your answer . (b) Solution of two electrolytes 'A' and 'B' are dilute . The limiting molar conductivity of 'B' increases to a smaller extent while that of 'A' increase to a much larger comparatively . Which of the two is a strong electrolyte ? justify your answere.

(a) Calculate the degree of dissociation 'A' and 'B' are dilute . The

1.	(a) Calculate the degree of dissociation 'A' and 'B' are dilute . The limiting molar conductivity of 'B' increases to a smaller extent while that 'A' increase to a much larger extent comparatively . Which of the two is a strong electrolyte ? Justify your answer . (b) Solution of two electrolytes 'A' and 'B' are dilute . The limiting molar conductivity of 'B' increases to a smaller extent while that of 'A' increase to a much larger comparatively . Which of the two is a strong electrolyte ? justify your answere.
Answer» Solution : According ti KOHLRAUSCH law `Lamda^(@)(CH_(3)COOH)= lamda_(H+)^(@)+lamda_(CH_(3)COO^(-))^(@)` `= 349.6+40.9=390Scm^(2)mol^(-1)` `Lamda_(m)= (Kxx1000)/(c )` `Lamda_(m)= (8.0xx10^(-5)Scm^(-1)xx1000cm^(3)L^(-1))/(0.0024molL^(-1)) = 33.33Scm^(2)mol^(-1)` `alpha=(Lamda_(m))/(Lamda_(m)^(@)` `alpha=(33.33Scm^(2)mol^(-1)/(390.5Scm^(2)mol^(-1)`= 0.085 Electrolyte B is a STRONG electrolyte . Limiting molar cinductivity increases only to a smaller extent for a strong , as on dilution the interaction are overcome . The degree if dissociation increases , therefore the number of ions in total volume of solution increases.