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(a) Calculate the emf of the cell in which the following reaction takes place Ni(S) + 2Ag^(+)(0.002M) rarr Ni^(2+)(0.160M) + 2Ag(S) Given that E_(cell)^(circ)= 1.05V (b) A galvanic cell after use is recharged by passing current through it. What type of cell is it? Give an example. |
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Answer» Solution :(a) Applying Nernst Equation, `E_(CELL) = E^(circ)_(cell) - 0.0591/n log[Ni^(2+)]/[Ag^(+)]^(2)` `= 1.05 - 0.02955 log (0.160)/(0.002)^(2) = 1.05 - 0.02955log(0.16)/(0.002)^(2)` `= 1.05 - 0.02955log 4 xx 10^(4) = 1.05 - 0.02955(log10000 + log 4)` `= 1.05 - 0.02955(4 +0.6021) = 0.914V` (b) Secondary cell e.g. Lead storage BATTERY |
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