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(a) Calculate the oxidation number of C in CH4 and in CH3Cl. (b) The sum of oxidation numbers of all atoms in a molecule is ……… |
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Answer» (a) CH4 ; x + (1 × 4) = 0 x + 4 = 0 x = -4 Oxidation number of C in CH4 is -4. CH3Cl: x + (3 × 1) + -1 = 0 x + 3 – 1= 0 x + 2 = 0 x = -2 Oxidation number of C in CH3Cl is -2. (b) Zero |
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