(a). Calculate triangleG_(f)^(@) of the following raection: Ag^(+)(aq)+Cl^(-)toAgCl(s) given triangleG_(f)^(@)(AgCl)=-109kJ//"mole",triangleG_(f)^(@)(Cl^(-))=-129kJ//"mole",triangleG_(f)^(@)(Ag^(+))=77kJ//"mole" Represent the above reaction in form of a cell. Calculate E^(@) of the cell. find log_(10)K_(sp) of AgCl at 25^(@)C (b). 6.539xx10^(-2)g of metallic Zn (atomic mass =65.39amu) was added to 100 mL of saturated solution of AgCl. Calculate log_(1)([Zn^(2+)])/([Ag^(+)]^(2)) at equilibrium at 25^(@)C given that Ag^(+)+e^(-)toAg""E^(@)=0.80V Zn^(2+)+2e^(-)toZn""E^(@)=-0.76V Also find how many moles of Ag will be formed (take (114)/(193)=0.59,(1.56)/(0.059)=26.44)

(a). Calculate triangleG_(f)^(@) of the following raection: Ag^(+)(aq

1.	(a). Calculate triangleG_(f)^(@) of the following raection: Ag^(+)(aq)+Cl^(-)toAgCl(s) given triangleG_(f)^(@)(AgCl)=-109kJ//"mole",triangleG_(f)^(@)(Cl^(-))=-129kJ//"mole",triangleG_(f)^(@)(Ag^(+))=77kJ//"mole" Represent the above reaction in form of a cell. Calculate E^(@) of the cell. find log_(10)K_(sp) of AgCl at 25^(@)C (b). 6.539xx10^(-2)g of metallic Zn (atomic mass =65.39amu) was added to 100 mL of saturated solution of AgCl. Calculate log_(1)([Zn^(2+)])/([Ag^(+)]^(2)) at equilibrium at 25^(@)C given that Ag^(+)+e^(-)toAg""E^(@)=0.80V Zn^(2+)+2e^(-)toZn""E^(@)=-0.76V Also find how many moles of Ag will be formed (take (114)/(193)=0.59,(1.56)/(0.059)=26.44)
Answer» Solution :(a). `triangleG_(R)^(@)=-109+129-77=-57kJ//mol` cell representation `Ag\|AgCl\|\|Cl^(-)\|Ag^(+)\|Ag`. `-1xx96500xxE^(@)=057xx10^(3)` `E^(@)=0.59"volt"` `0=0.59-(0.059)/(1)log((1)/(K_(SP)))` `logK_(SP)=-10`. (b). `ZntoZn^(2+)+2e^(-),""0.76"volt"` `underline(2Ag^(+)+2e^(-)to2Ag,""0.80"volt")` `underline(Zn+2Ag^(+)toZn^(2+)+2Ag,) ""E_(cell)^(@)=1.56"volt"` `n_(2n)=(6.539)/(65.39)=10^(-3)mol""[Ag^(+)]=sqrt(K_(sp))=10^(-5)M` `0=1.56-(0.059)/(2)logK""n_(Ag^(+))=10^(-5)xx0.1=10^(-6)M`. `n_(Ag)=10^(-6)molimplieslogK=52.8`