A calorimeter contains 10 g of water at 20^(@)C. The temperature falls to 15^(@)C in 10 min. When calorimeter contains 20 g of water at 20^(@)C, it takes 15 min for the temperature to become 15^(@)C. Find the water equivalent of the calorimeter.

A calorimeter contains 10 g of water at 20^(@)C. The temperature falls

1.	A calorimeter contains 10 g of water at 20^(@)C. The temperature falls to 15^(@)C in 10 min. When calorimeter contains 20 g of water at 20^(@)C, it takes 15 min for the temperature to become 15^(@)C. Find the water equivalent of the calorimeter.
Answer» Solution :(i) LET water equivalent be `x` `(10 + x) s (Delta THETA)/(Delta t) = - k' (bartheta - theta_(0))` (b) `(10 + x) s ((20 - 15))/(10) = - k' ((20 + 15)/(2) - theta_(0))` `(20 + x) s ((20 - 15))/(10) = - k' ((20 + 15)/(2) - theta_(0))` `(10 + x)/(10) = (20 + x)/(15)` `150 + 15 x = 200 + 10 x` `5x = 50 IMPLIES x = 10 g`